2025-10-17
1,751 reads
2025-10-17
1,751 reads
2024-10-16
454 reads
2021-12-08
639 reads
2021-09-20
690 reads
2020-03-17
737 reads
2021-03-26 (first published: 2018-12-10)
13,443 reads
2018-07-09
1,646 reads
2017-12-11
1,071 reads
Aaron Bertrand rounds out his series on STRING_SPLIT() in SQL Server 2016 with additional tests comparing splitting techniques to TVPs.
2016-06-09
4,804 reads
Aaron Bertrand follows up on a recent post about the performance of STRING_SPLIT() with a few additional reader-motivated tests.
2016-05-04
3,767 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
hi, i noticed the sqlhealth extended event is on by default , and it...
Using New-AzSqlInstanceServerTrustCertificate to import a certificate and get the message New-AzSqlInstanceServerTrustCertificate: Long running operation...
Comments posted to this topic are about the item Refactoring SQL Code, which is...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers