2011-10-06 (first published: 2009-12-02)
9,344 reads
2011-10-06 (first published: 2009-12-02)
9,344 reads
2011-10-04 (first published: 2009-11-26)
11,101 reads
2011-09-29 (first published: 2009-11-18)
10,430 reads
2011-09-27 (first published: 2009-10-28)
9,664 reads
2011-09-22 (first published: 2009-10-21)
10,923 reads
2011-09-20 (first published: 2009-10-14)
9,999 reads
2011-09-15 (first published: 2009-10-07)
8,025 reads
2011-09-13 (first published: 2009-09-30)
8,052 reads
2011-09-08 (first published: 2009-09-23)
6,743 reads
When a job is too simple to be done in-house, how far down the phylogenetic tree should you go?
2011-09-06 (first published: 2009-09-16)
7,659 reads
By Patrick
SQL Server Audit is an efficient way to track and log events that occur...
I presented at SQL Saturday Pittshburgh this past weekend about populating your data warehouse...
By Steve Jones
A customer was asking recently about the RPO for their estate, and I showed...
I am trying to access LocalDB 2012 on my Windows 7 SP1 PC. I...
Comments posted to this topic are about the item The Modern Algorithm of Chance
Comments posted to this topic are about the item Use Logic Apps To Save...
I have this data in my Customer table:
CustomerID CustomerName 1 Steve 2 Andy 3 Brian 4 Allen 5 DevinI run this code:
SELECT t.CustomerID , c.value FROM ( SELECT CustomerID , STRING_AGG (CustomerName, ',') AS me FROM customer GROUP BY CustomerID) t CROSS APPLY STRING_SPLIT(me, ',') c;What is returned? See possible answers