2011-11-15 (first published: 2010-03-03)
9,822 reads
2011-11-15 (first published: 2010-03-03)
9,822 reads
2011-11-08 (first published: 2010-02-10)
11,423 reads
2011-11-03 (first published: 2010-02-03)
12,678 reads
2011-11-01 (first published: 2010-01-27)
10,644 reads
2011-10-27 (first published: 2010-01-20)
11,459 reads
2011-10-25 (first published: 2010-01-06)
11,558 reads
A tale from the days when civilization was young and everything was harder than it is now.
2011-10-20 (first published: 2009-12-30)
10,714 reads
2011-10-18 (first published: 2009-12-23)
9,295 reads
2011-10-13 (first published: 2009-12-16)
8,806 reads
2011-10-11 (first published: 2009-12-09)
9,708 reads
By Patrick
SQL Server Audit is an efficient way to track and log events that occur...
I presented at SQL Saturday Pittshburgh this past weekend about populating your data warehouse...
By Steve Jones
A customer was asking recently about the RPO for their estate, and I showed...
I am trying to access LocalDB 2012 on my Windows 7 SP1 PC. I...
Comments posted to this topic are about the item The Modern Algorithm of Chance
Comments posted to this topic are about the item Use Logic Apps To Save...
I have this data in my Customer table:
CustomerID CustomerName 1 Steve 2 Andy 3 Brian 4 Allen 5 DevinI run this code:
SELECT t.CustomerID , c.value FROM ( SELECT CustomerID , STRING_AGG (CustomerName, ',') AS me FROM customer GROUP BY CustomerID) t CROSS APPLY STRING_SPLIT(me, ',') c;What is returned? See possible answers