Miscellaneous

Technical Article

Function to encript password

  • Script

If you need to save password for you application in tables, with this function you can save them encripted. And with another published function (check the page to find the script) you can desencript it. The function receives the password,  modifies every character and returns the encripted password.

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2004-03-18

654 reads

SQLServerCentral Article

Review of Programming Microsoft SQL Server 2000 with Microsoft Visual

  • Article

We get books in occasionally for review and have started making them available to our existing authors. Jim was interested in this one - turns out he didn't find much to like. If you're a beginner it might be a better fit. Or maybe you've read the book and disagree?

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2004-03-16

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Technical Article

Difference between dates with thousands separators

  • Script

This function calculates the time difference between 2 datetimes and displays the results in the following format:H,HHH,HHH:MM:SSThe return is a 15 character field that is left padded with spaces so that the field becomes right justified.  This makes the colons line up for easy reading.  Commas are automatically added as thousands separators as needed by […]

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2004-03-14

478 reads

Technical Article

tighter approach to counting strings in strings

  • Script

Saw Mike's routine for counting occurences of a string in a string and I thought I'd offer a simpler solution.Simply replace the occurence with null and use length differences as shown.NOTE: len may ignore trailing spaces, so this can be made more solid by adding some non printable char (less likely to interfere with operation) […]

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2004-03-10

113 reads

Technical Article

Count number of strings within a string

  • Script

This function will return the number of occurrences of one string within another string. I was looking for something like this recently, and the only thing I could find was needlessly complicated. Don't forget, when calling a scalar function, you must qualify with username like this:Select dbo.StringCount('Hi There','e') This function may be a little too […]

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2004-03-09

404 reads

Blogs

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Forums

Pay for Performance

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Pay for Performance, which is...

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Question of the Day

Too Many Choices

I have a table, dbo.MasterBrands, with this data:

BrandID OfficialName
1       Samsung
2       Apple
3       Microsoft
4       Adidas
5       Coca-Cola
I run this query. What is returned for Coca-Cola?
SELECT CHOOSE(BrandID, 'Conglomerate', 'Tech and Design', 'Desktop', 'Apparel')
FROM dbo.MasterBrands;

See possible answers