If you need to save password for you application in tables, with this function you can save them encripted. And with another published function (check the page to find the script) you can desencript it. The function receives the password, modifies every character and returns the encripted password.
2004-03-18
593 reads
Dinesh did a little research on nulls and was kind enough to package it up for us. How many of you know or use NULLIF? Or COALESCE? Handy stuff!
2004-03-18
10,160 reads
We get books in occasionally for review and have started making them available to our existing authors. Jim was interested in this one - turns out he didn't find much to like. If you're a beginner it might be a better fit. Or maybe you've read the book and disagree?
2004-03-16
4,913 reads
If you need to alter existing datatypes in the event of a SQL Server Datatype issue for capacity planning or conversion process this simple schema script may come in handy
2004-03-15
126 reads
A very short article that discusses how nulls can ruin your day if you don't understand how they behave when you concatenate.
2004-03-15
6,079 reads
This function calculates the time difference between 2 datetimes and displays the results in the following format:H,HHH,HHH:MM:SSThe return is a 15 character field that is left padded with spaces so that the field becomes right justified. This makes the colons line up for easy reading. Commas are automatically added as thousands separators as needed by […]
2004-03-14
417 reads
Saw Mike's routine for counting occurences of a string in a string and I thought I'd offer a simpler solution.Simply replace the occurence with null and use length differences as shown.NOTE: len may ignore trailing spaces, so this can be made more solid by adding some non printable char (less likely to interfere with operation) […]
2004-03-10
79 reads
Regular columnist Chris Hedgate follow up on Andy's recent article about Worst Practices with one of his own. This is worth passing on to your development team.
2004-03-10
17,318 reads
This function will return the number of occurrences of one string within another string. I was looking for something like this recently, and the only thing I could find was needlessly complicated. Don't forget, when calling a scalar function, you must qualify with username like this:Select dbo.StringCount('Hi There','e') This function may be a little too […]
2004-03-09
300 reads
This function returns the difference between dates in the HH:MM:SS format.
2004-09-27 (first published: 2004-03-08)
106 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
Comments posted to this topic are about the item Cleaning Up the Cloud
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')
I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON
INSERT dbo.TravelLog
(
TravelLogID,
CityID,
StartDate,
EndDate
)
VALUES
(25, 5, '2025-09-12', '2025-09-17')
SET IDENTITY_INSERT dbo.TravelLog OFF
I now run this code.
DBCC CHECKIDENT(TravelLog)
GO
INSERT dbo.TravelLog
(
CityID,
StartDate,
EndDate
)
VALUES
(4, '2025-10-14', '2025-10-17')
GO
What is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025?
See possible answers