Writing as an Art and a Job
Steve thinks communication is a core sill for technology people, especially in the age of AI.
2026-03-06
93 reads
Steve thinks communication is a core sill for technology people, especially in the age of AI.
2026-03-06
93 reads
This week I had the opportunity to join many of the U.S.-based Redgaters in Austin to talk about 2024 plans, hear from the product teams, and have some much-needed fellowship. One thing was particularly clear as I listened to various leaders and product managers – the customer drives everything we do. And I have to […]
2024-01-20
92 reads
Communication can be challenging when we don't work closely with others. Steve draws a comparison with a popular children's show in the US.
2023-08-14
160 reads
Steve notes that sometimes we message too often, but that's a human problem, not a tool issue.
2023-06-02
161 reads
The use of messaging dominates communication for Steve. Can you say the same thing?
2022-09-23
115 reads
2020-05-18
155 reads
Steve notes we all need to learn to communicate and share information better, especially while we are remote.
2020-05-14
128 reads
After installing Microsoft Teams, Steve has a bit of communication overload.
2019-05-13
221 reads
2016-05-02
113 reads
By Steve Jones
Here are the resources for my talk at Day of Data Boston. Slides –...
By Steve Jones
I’ve covered the values in a number of previous posts on the Book of...
By Arun Sirpal
When the evidence names the database, it says so. When it doesn’t, it stops....
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers