2023-08-07 (first published: 2009-11-10)
3,550 reads
2023-08-07 (first published: 2009-11-10)
3,550 reads
If you need to connect to a SQL server and don't have the 'sa' password plus the builtin\administrators account has been removed then Rudy Panigas shows us what you need to know.
2011-03-11 (first published: 2009-11-03)
30,515 reads
Returns records with errors from the default trace ordered by most recent first
2009-11-12 (first published: 2009-10-29)
702 reads
This procedure checks if a mirror treshold exists and wait until this treshold is cleared or after a specified time.
2009-11-10 (first published: 2009-10-23)
499 reads
There are times when maintenance plan is too simple to do the job, and SSIS is unreachable for you. Here is a simple stored procedure to help you.
2009-11-05 (first published: 2009-10-09)
1,549 reads
Searches for foreign key constraints that don't have fully matching indexes. The best partial matching indexes are outputted with MatchCounts and column comparisons.
2009-10-15 (first published: 2009-10-01)
1,914 reads
2009-10-09 (first published: 2009-09-29)
2,081 reads
Part 2 of the SQL Server Essentials Series looks at why you should be using the Full Recovery Model to protect your data assets.
2009-09-21
9,098 reads
A new article from Paul Els looks at managing free space on your database servers by finding detached databases and old backup files.
2009-09-10
5,605 reads
2009-09-04
3,999 reads
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
By ChrisJenkins
Have you been thinking about migrating your reporting to Microsoft Fabric or Snowflake but...
The Joyful Craftsmen has become the new owner of Revolt BI. The merger creates...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
Comments posted to this topic are about the item Concurrency and Baseline Control: Level...
Comments posted to this topic are about the item Spending Time in the Office
I have this code on SQL Server 2022. What happens when it runs all at once?
DROP TABLE IF EXISTS dbo.Commission GO CREATE TABLE dbo.Commission (id INT NOT NULL IDENTITY(1,1) CONSTRAINT CommissionPK PRIMARY KEY , salesperson VARCHAR(20) , commission VARCHAR(20) ) GO INSERT dbo.Commission ( salesperson, commission) VALUES ( 'Brian', 12 ), ( 'Brian', 'None' ) GOSee possible answers