2011-08-24
10 reads
2011-08-24
8 reads
2011-08-24
7 reads
2011-08-24
45 reads
Prepare Windows 7 to create Hyper-V Virtual lab to implement SQL Server 2008 R2 SP1 Active/Active Cluster
This series of Videos will walk through how to prepare existing windows 7 machine to test and validate active/active node...
2011-08-24
1,306 reads
SQLMCM Training – Day 16
Today Bob spoke the whole day about securing SQL Server, security itself, and encrypting
data. It was really hard content, and...
2011-08-24
641 reads
A Couple of Data Compression Tricks in SQL Server 2008
As I have said several times before, I am a big fan of data compression in SQL Server 2008 and...
2011-08-23
1,934 reads
Interview with SQL Server MVP Grant Fritchey
Grant Fritchey will be speaking at the SQLServerCentral.com track at SQL Server Connections, October 31-November 3, 2011, in Las Vegas,...
2011-08-23
1,644 reads
Get All SESSIONPROPERTY Values for Your Session
As a follow-up to my SERVERPROPERTY() post, this is a quick script to grab all the SESSIONPROPERTY() values from your current session in a table. Useful when you forget...
2011-08-23
26 reads
Get All SESSIONPROPERTY Values for Your Session
As a follow-up to my SERVERPROPERTY() post, this is a quick script to grab all the SESSIONPROPERTY() values from your...
2011-08-23
866 reads
Blogs
The SUM of Nothing: #SQLNewBlogger
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
How to Move the SSMS Status Bar to the Top and Color-Code SQL Server Connections
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
Forums
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Question of the Day
Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers