2014 PASS Summit 2014 Board Q&A Notes
As has occurred in previous years at the PASS Summit the PASS Board of Directors held an open Q&A session...
2014-11-17
694 reads
As has occurred in previous years at the PASS Summit the PASS Board of Directors held an open Q&A session...
2014-11-17
694 reads
Last week before our monthly MagicPASS meeting I went through my usual routine of grabbing the PASS chapter deck and...
2014-09-23
521 reads
Thursday night (8/28) I'll be presenting Inspector Insert And The Case Of The Mistaken IDENTITY for the Orlando SQL User...
2014-08-27
1,184 reads
The session lineup for the 2014 PASS Summit was announced today and I'm honored to be selected as a presenter....
2014-06-25
1,328 reads
The 2014 PASS election cycle begins today when voting opens for the Nomination Committee (NomCom) and I'm one of eleven...
2014-06-03
1,115 reads
I suspect most DBAs have a script in their T-SQL toolbelt which scripts out database permissions for a specific user...
2014-02-04
1,106 reads
Tablediff is a command line utility that comes with SQL Server to compare the data and schema in two tables...
2013-12-05
2,563 reads
Windows 8.1 was released to the Windows Store last week and aside from having to download the same 3.9 GB...
2013-10-22
1,203 reads
I'm at the 2013 PASS Summit in Charlotte, NC, this week, and presented a session about documenting your databases using...
2013-10-17
1,275 reads
In less than 72 hours I'll be in Charlotte with over 3,000 of my closest SQL Server friends for the...
2013-10-11
706 reads
By Steve Jones
I wrote about learning today for the editorial: I Can’t Make You Learn. I...
By ReviewMyDB
Fabric has CI/CD built in, but if you've tried to use it for database...
By Steve Jones
attriage – n. the state of having lost all control over how you feel...
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In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers