New Blog Feed URL
Not easy to find yet on the new site, you can find it at http://www.sqlandy.com/feed/.
2010-01-05
316 reads
Not easy to find yet on the new site, you can find it at http://www.sqlandy.com/feed/.
2010-01-05
316 reads
Bill Graziano posted some thoughts about the merits of East Coast vs West Coast placement of the Summit. He did...
2010-01-05
374 reads
As a part of my DB documentation process for a large database, I needed a method to quickly show me...
2010-01-05
718 reads
We have a lot of administrative tools for SQLServerCentral that are available online. Most of the work I do can...
2010-01-05
399 reads
In September 1986 my family returned to Beaufort, SC, from a three year tour stationed at MCAS Iwakuni, Japan. My father was...
2010-01-05
660 reads
2010-01-04
760 reads
I’ve been ‘on vacation’ for two weeks and it’s been nice to relax. I wasn’t able to unplug entirely, but...
2010-01-04
457 reads
Well, now that the holidays are over and the Consumer Electronics Show (CES) is nearly upon us, we are starting...
2010-01-04
639 reads
If you have been following this series we have covered system buses, hard disks, host bus adapters and RAID. Along...
2010-01-04
46,932 reads
I’ve had a few people ask me this question. It’s the new year, many people are making New Year’s resolutions,...
2010-01-04
804 reads
By Steve Jones
I wrote about learning today for the editorial: I Can’t Make You Learn. I...
By ReviewMyDB
Fabric has CI/CD built in, but if you've tried to use it for database...
By Steve Jones
attriage – n. the state of having lost all control over how you feel...
Comments posted to this topic are about the item SSRS Reminded Me of the...
I have a need to execute a stored procedure and return the results to...
Title pretty much says it all - can this be done? I've tried several...
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers