Why Use TRY_PARSE(): #SQLNewBlogger
Someone asked why I would use TRY_PARSE after I posted a question at SQL Server Central: Getting the Average. Isn’t is slower? A fair question. This quick post looks...
2026-08-12
219 reads
Someone asked why I would use TRY_PARSE after I posted a question at SQL Server Central: Getting the Average. Isn’t is slower? A fair question. This quick post looks...
2026-08-12
219 reads
This month we have a new host, which I am grateful for. So many people have stopped blogging that it’s a challenge to keep this going. Jeff Taylor has...
2026-08-11
142 reads
I wrote earlier this week about the SQL MCP Server using the Data API Builder. In that post I showed how to query the MCP server from VSCode, but...
2026-08-10 (first published: 2026-07-29)
571 reads
I was recently trying to handle a simple task with a few AI tools to see how well things worked. I realized that AI isn’t great for everything and...
2026-08-10
436 reads
2026-08-10
598 reads
Today Steve notes that he often compares the work a computer does to what might happen if the same actions occurred in the physical world.
2026-08-10
159 reads
2026-08-07
896 reads
It’s been some time since I provided a car update, so I decided to showcase a few things I’ve learned about my cars since the last one. In this...
2026-08-07
171 reads
2026-08-07
234 reads
2026-08-05
683 reads
By James Serra
Microsoft shared a broad set of Fabric, Power BI, and SQL updates at FabCon...
By Steve Jones
No, I’m not quitting or retiring. Just going on vacation, but I leave tonight...
Comments posted to this topic are about the item Let's Talk Certifications, which is...
Comments posted to this topic are about the item The Hidden Security Risks of...
Comments posted to this topic are about the item The Empty Aggregate
I have this table in a SQL Server 2025 database:
CREATE TABLE [dbo].[CustomerOrder] ( [OrderID] [int] NULL, [CustomerID] [int] NULL, [total] [money] NULL ) ON [PRIMARY] GOWhat is returned from this code? (answers are for the sum and then the count)
SELECT SUM(total) AS sum,
COUNT(total) AS count
FROM dbo.CustomerOrder;
See possible answers