What Can You Do?
Security alerts and concerns are serious, but that doesn't mean that everyone will treat them that way.
2015-10-05
95 reads
Security alerts and concerns are serious, but that doesn't mean that everyone will treat them that way.
2015-10-05
95 reads
It’s been a long time since I wrote about my workspace, however I made a change recently. This was the...
2015-10-02
369 reads
It’s been a long time since I wrote about my workspace, however I made a change recently. This was the...
2015-10-02
623 reads
Another post for me that is simple and hopefully serves as an example for people trying to get blogging as...
2015-10-02 (first published: 2015-09-24)
2,709 reads
2015-10-02
1,252 reads
I learned a new trick with SQL Data Generator that I wasn’t aware of previously. I think this is a...
2015-09-30
1,005 reads
Last week we received the results of the PASS Board of Directors elections for 2015. Jen Stirrup and Tim Ford...
2015-09-29
815 reads
Last week we received the results of the PASS Board of Directors elections for 2015. Jen Stirrup and Tim Ford...
2015-09-29
982 reads
2015-09-29
1,585 reads
I’ve been looking to work on my programming skills a bit and try some new languages. I’d like to grow...
2015-09-28
486 reads
By ReviewMyDB
My T-SQL Tuesday #202 entry for Marlon Ribunal's invitation on memorable SQL Server outages....
A RAG pipeline that answers questions in the demo is not the same thing...
By Steve Jones
“A multitude of bad ideas is necessary for one good idea” – from Excellent...
Comments posted to this topic are about the item Adding new column with DEFAULT
I've got a web application for my side business. I've added a SQL Server...
Comments posted to this topic are about the item Looking for New Blood
Which number will the COUNT() return after executing the following statements:
DROP TABLE IF EXISTS #test; CREATE TABLE #test (id INT) INSERT INTO #test (id) SELECT * FROM GENERATE_SERIES(1, 3) AS gs ; ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0; go UPDATE #test SET flag = 0 WHERE id = 1 UPDATE #test SET flag = 1 WHERE id = 2 INSERT INTO #test (id) VALUES (4) SELECT COUNT(*) FROM #test AS t WHERE flag = 0See possible answers