Steve Jones

My background is I have been working with computers since I was about 12. My first "career" job in this industry was with network administration where I became the local DBA by default. I have also spent lots of time administering Netware and NT networks, developing software, managing smaller IT groups, making lots of coffee, ordering pizza for late nights, etc., etc.

I currently am the editor of SQL Server Central and an advocate/architect at Redgate Software. I am also the President of SQL Saturday, maintain the T-SQL Tuesday monthly party, and remember our colleagues at sqlmemorial.org.

You can find out more about me on my blog (www.voiceofthedba.com) or LinkedIn (www.linkedin.com/in/way0utwest)
  • Interests: yoga, reading, biking, snowboarding, volleyball

SQL Cookbook: Query Solutions and Techniques for All SQL Users

You may know SQL basics, but are you taking advantage of its expressive power? This second edition applies a highly practical approach to Structured Query Language (SQL) so you can create and manipulate large stores of data. Based on real-world examples, this updated cookbook provides a framework to help you construct solutions and executable examples in several flavors of SQL, including Oracle, DB2, SQL Server, MySQL, and PostgreSQL.

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2025-08-18 (first published: )

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Question of the Day

The Tightly Linked View

I try to run this code on SQL Server 2022. All the objects exist in the database.

CREATE OR ALTER VIEW OrderShipping
AS
SELECT cl.CityNameID,
       cl.CityName,
       o.OrderID,
       o.Customer,
       o.OrderDate,
       o.CustomerID,
       o.cityId
 FROM dbo.CityList AS cl
 INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID
GO
CREATE OR ALTER FUNCTION GetShipCityForOrder
(
    @OrderID INT
)
RETURNS VARCHAR(50)
WITH SCHEMABINDING
AS
BEGIN
    DECLARE @city VARCHAR(50);
    SELECT @city = os.CityName
    FROM dbo.OrderShipping AS os
    WHERE os.OrderID = @OrderID;
    RETURN @city;
END;
go
What is the result?

See possible answers