2019-07-23
678 reads
2019-07-23
678 reads
2019-07-22
773 reads
This post continues looking at some of the Kubernetes concepts I’ve been learning with the 50 days of Kubernetes (K8s). Specifically in this post, I’m writing and thinking about...
2019-07-22
29 reads
AMD has new chips coming out and Glenn Berry changes his recommendation against using AMD in SQL Servers.
2019-07-20
192 reads
Steve doesn't think Windows containers are the future for the data platform.
2019-07-19
516 reads
2019-07-19
961 reads
2019-07-18
660 reads
AI software is being used to manage the daily work of some employees. Is this a trend that is good or bad?
2019-07-18
201 reads
2019-07-17
603 reads
Microsoft has embraced open source software, and has opened much of their code. They have also proven that DevOps development can scale in this environment.
2019-07-17
205 reads
By HeyMo0sh
Over time, I’ve realised that one of the hardest parts of cloud management isn’t...
By HeyMo0sh
One of the biggest challenges I’ve faced in cloud operations is maintaining clear visibility...
By Steve Jones
I come to Heathrow often. Today is likely somewhere close to 60 trips to...
Comments posted to this topic are about the item Fun with JSON II
Comments posted to this topic are about the item Changing Data Types
Comments posted to this topic are about the item Answering Questions On Dropped Columns
I have some data in a table:
CREATE TABLE #test_data
(
id INT PRIMARY KEY,
name VARCHAR(100),
birth_date DATE
);
-- Step 2: Insert rows
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT t1.[key] AS row,
t2.*
FROM OPENJSON(
(
SELECT t.* FROM #test_data AS t FOR JSON PATH
)
) t1
CROSS APPLY OPENJSON(t1.value) t2; See possible answers