2018-04-19 (first published: 2018-04-12)
4,227 reads
2018-04-19 (first published: 2018-04-12)
4,227 reads
Rename Foreign Key Constraints in a consistent manner. Ideal for preventing constraint errors during code promotion.
2018-04-13 (first published: 2013-03-19)
1,361 reads
Create views based on table definitions for backwards compatibility when relocating tables to a new database.
2013-08-16 (first published: 2013-07-30)
1,115 reads
Outputs an easily readable result of the database and server roles for database principals.
2013-08-05 (first published: 2013-06-14)
1,063 reads
Find all columns containing a string value across all tables and schemas.
2012-11-07 (first published: 2012-10-12)
2,058 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
Hi, in a simple oledb source->derived column->oledb destination data flow, 2 of my...
hi, i noticed the sqlhealth extended event is on by default , and it...
Using New-AzSqlInstanceServerTrustCertificate to import a certificate and get the message New-AzSqlInstanceServerTrustCertificate: Long running operation...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers