2023-12-27
483 reads
2023-12-27
483 reads
2023-10-27
434 reads
2023-10-20
454 reads
2018-08-27
852 reads
2018-06-05
868 reads
2016-08-16
1,335 reads
2016-08-02
1,363 reads
2016-07-05 (first published: 2016-05-26)
4,776 reads
Learn how trusted foreign keys (FK) can help or hurt performance.
2018-08-24 (first published: 2016-03-08)
6,799 reads
Understand what FK's do and how they use indexes. Then use my script to see if they're using good indexes.
2018-06-29 (first published: 2016-02-10)
6,134 reads
By Steve Jones
This value is something that I still hear today: our best work is done...
By gbargsley
Have you ever received the dreaded error from SQL Server that the TempDB log...
By Chris Yates
Artificial intelligence is no longer a distant concept. It is here, embedded in the...
You need line editing for books! A line editor smooths out your writing, sentence by...
We have a BI-application that connects to input tables on a SQL Server 2022...
At work we've been getting better at writing what's known as GitHub Actions (workflows,...
I try to run this code on SQL Server 2022. All the objects exist in the database.
CREATE OR ALTER VIEW OrderShipping AS SELECT cl.CityNameID, cl.CityName, o.OrderID, o.Customer, o.OrderDate, o.CustomerID, o.cityId FROM dbo.CityList AS cl INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID GO CREATE OR ALTER FUNCTION GetShipCityForOrder ( @OrderID INT ) RETURNS VARCHAR(50) WITH SCHEMABINDING AS BEGIN DECLARE @city VARCHAR(50); SELECT @city = os.CityName FROM dbo.OrderShipping AS os WHERE os.OrderID = @OrderID; RETURN @city; END; goWhat is the result? See possible answers