2017-11-16
744 reads
2017-11-16
744 reads
2017-05-23
932 reads
2017-05-01
875 reads
When we start working as developer or learning, we often
face this issue. Where is the best tutorials, books and other...
2017-04-10
276 reads
Requirement: Recently we got the information from management
that our project will be getting the customers from China, so our application
should...
2017-03-28
145 reads
In this article I will be listing the tips and tricks to work like
a Pro.
So let's get started –
Important keyboard...
2017-02-20
254 reads
I will be writing
this article in four parts because this topic is huge and the amount of
information can be overwhelming...
2017-02-06
548 reads
This is not an article or a script. I am posting this just to share my experience and I feel...
2017-01-30
920 reads
There are many situations when we want to know the size of our database tables or just need a list...
2017-01-19
685 reads
I will be writing this series of articles for the Special Indexes in SQL Server. In this series we will...
2016-11-11
499 reads
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
SELECT * feels convenient, but in SQL Server it bloats I/O, burns network bandwidth,...
India's top proficiency testing facility is Fare Labs. We employ particular metrics or evaluations...
I've noticed several instances of what looks like a recursive insert with the format:...
Comments posted to this topic are about the item Cleaning Up the Cloud
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers