Sql Server - Find and Replace a value across all tables in database
Find and Replace a value across all tables in database
In my project I faced this problem due to typing mistakes....
2016-08-31
567 reads
Find and Replace a value across all tables in database
In my project I faced this problem due to typing mistakes....
2016-08-31
567 reads
Monitoring the Performance of All Stored Procedures
Every Project suffer from this problem, over the time they
have developed many stored procedure...
2016-08-31
458 reads
Monitoring the Performance of All Stored Procedures
Every Project suffer from this problem, over the time they
have developed many stored procedure...
2016-08-31
580 reads
Index Utilization Report
One day my manager came and told me that he need Index Utilization Report.
He felt that during...
2016-08-29
569 reads
1. Tell me about yourself.
Answer - Give summary of your past education and work, skills, and achievements and include your strong...
2016-03-27
143 reads
Interview is a three stage process. Before => Interview => After
A. Before Interview -
1. Most important, ready your Resume/CV. Be confident about...
2016-03-26
155 reads
By Vinay Thakur
Continuing from Day 4 where we learned Encoder, Decoder, and Attention Mechanism, today we...
By Vinay Thakur
Continuing from Day 3 where we covered LLM models open/closed and their parameters, Today...
By Steve Jones
One of the nice things about Flyway Desktop is that it helps you manage...
I'm fairly certain I know the answer to this from digging into it yesterday,...
Hi Team, I am trying to refresh the Azure Synapse Dedicated pool from production...
hi everyone I am not sure how to write the query that will produce...
I have some data in a table:
CREATE TABLE #test_data
(
id INT PRIMARY KEY,
name VARCHAR(100),
birth_date DATE
);
-- Step 2: Insert rows
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT *
FROM OPENJSON(
(
SELECT t.* FROM #test_data AS t FOR JSON PATH
)
) t; See possible answers