Writing Nearly Codeless Apps: Part 5
In this next installment of the series on writing codeless applications, David Ziffer looks at the querying of data from the database.
2010-11-03
5,393 reads
In this next installment of the series on writing codeless applications, David Ziffer looks at the querying of data from the database.
2010-11-03
5,393 reads
Part four of this series on rapid application development looks at the CRUD routines that are needed for almost every application.
2010-10-27
7,067 reads
As we continue in this series, see how auditing tables are used to track all changes that are made to the main data tables.
2010-10-20
8,293 reads
In this article, learn why it makes sense to build a more standarized, more robust database based on rules and see how data modeling works in the RAP software.
2010-10-13
10,563 reads
A new series from David Ziffer describes a way of building applications in a more standardized fashion, and it provides a basic review of some software that can help.
2010-10-06
18,413 reads
Comparing data from two queries to see if they return the same results can be an interesting challenge. David Ziffer brings us a great way to do this using Excel.
2008-12-31
1,351 reads
Exporting data from your database and building reports is easy with Reporting Services, but sometimes you need to use other sources
2008-11-05
18,161 reads
Auditing is becoming more important all the time for DBAs as regulations and requirements increase. Building auditing into your systems can be done a number of ways, but with SQL Server 2005, you have a new option. New author David Ziffer brings us a generic auditing CLR trigger.
2006-08-02
19,059 reads
By Steve Jones
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I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers