A Travel Milestone: Two Keystones
I used to travel a lot. Last year I flew over 140,000 miles in the air, drive another 1000 or so on vacation, and visited numerous countries. It’s hectic...
2020-07-17
28 reads
I used to travel a lot. Last year I flew over 140,000 miles in the air, drive another 1000 or so on vacation, and visited numerous countries. It’s hectic...
2020-07-17
28 reads
I’ve started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2020-07-17
6 reads
2020-07-17
429 reads
Today Steve thinks about what to do when planning for your digital assets after you pass.
2020-07-17
369 reads
When we need to delegate work to less privileged users, Steve has an idea.
2020-07-16
198 reads
I’ve started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2020-07-16
7 reads
2020-07-16
670 reads
Another post for me that is simple and hopefully serves as an example for people trying to get blogging as #SQLNewBloggers. I saw a question recently about getting the...
2020-07-16 (first published: 2020-07-06)
296 reads
Learn the basics of how Row-Level Security works in SQL Server.
2020-07-15 (first published: 2017-12-28)
5,798 reads
2020-07-15
179 reads
By Steve Jones
“Don’t aim to have others like you; aim to have them respect you.” –...
Many years ago, before I joined Oracle, I was working on a major modernisation...
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
Comments posted to this topic are about the item Is Fabric a Reliable Service...
hi , a new user wants to be able to add sql agent jobs...
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers