2013-07-22 (first published: 2009-04-30)
3,909 reads
2013-07-22 (first published: 2009-04-30)
3,909 reads
2013-07-19 (first published: 2013-07-01)
670 reads
Outputs an easily readable result of the database and server roles for database principals.
2013-07-18 (first published: 2013-06-14)
1,085 reads
Records snapshots of space usage & buffer cache usage stats by partition, index, table, schema, filegroup, & database. Stats incl Reserved, Used, Data, buffer cache for row, lob, & overflow.
2013-07-17 (first published: 2009-05-30)
2,821 reads
Split a string with separator without looping. Can be efficiently used with joins if necessary.
2013-07-12 (first published: 2013-06-15)
2,466 reads
2013-07-10 (first published: 2013-06-19)
1,675 reads
This is a stored procedure to add a columns to multiple tables, if column doesn't exist
2013-07-09 (first published: 2008-05-27)
993 reads
This will generate a script that drops and recreates existing db mail accounts and change the smpt server.
2013-07-08 (first published: 2013-06-19)
841 reads
2013-07-03 (first published: 2013-06-07)
925 reads
I wrote this script to help determine which data files are taking up space on an instance.
2013-07-02 (first published: 2013-06-05)
1,626 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers