2015-10-19 (first published: 2013-08-30)
4,404 reads
2015-10-19 (first published: 2013-08-30)
4,404 reads
2015-10-16 (first published: 2013-05-30)
5,758 reads
This script will help you to get the culprit along with IP address and User name which helps us to determine the Blocking root cause.
2015-10-14 (first published: 2013-12-08)
4,453 reads
List all tables in a SQL Server database with the details of them.
2015-10-13 (first published: 2013-02-20)
4,592 reads
To get the IP addresses of Multiple hostnames from below stored procedure.
2015-10-12 (first published: 2013-04-17)
5,830 reads
2015-10-09 (first published: 2014-03-21)
5,034 reads
2015-10-08 (first published: 2015-07-02)
1,121 reads
2015-10-07 (first published: 2015-09-18)
1,650 reads
Sometime due to the heavy load in Exchange servers we received configuration alerts notifications and report delay and that time it is require to move to some other exchange servers to full fill the requirement during the critical periods.
2015-10-06 (first published: 2014-12-19)
1,131 reads
Creates a record of all or part of a Windows PowerShell session in a text file.
2015-10-02 (first published: 2015-09-17)
1,157 reads
By Steve Jones
Here are the resources for my talk at Day of Data Boston. Slides –...
By Steve Jones
I’ve covered the values in a number of previous posts on the Book of...
By Arun Sirpal
When the evidence names the database, it says so. When it doesn’t, it stops....
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers