2010-03-29 (first published: 2010-03-24)
1,838 reads
2010-03-29 (first published: 2010-03-24)
1,838 reads
Here is a one more very quick way to find row count for a table.
2010-03-26 (first published: 2010-03-23)
5,383 reads
Evaluate credit card numbers based on ISO 2894 algorithm.
2010-03-24 (first published: 2010-03-17)
1,923 reads
This script displays Phonetic Pronunciation of a given password
2010-03-22 (first published: 2010-03-12)
1,391 reads
2010-03-17 (first published: 2010-03-04)
1,531 reads
A super-powered EXEC on steroids, the Power Tool every DBA wants for Christmas.
2010-03-16 (first published: 2010-03-04)
2,931 reads
This Script is used to List out the objects lying in the box which were un used from the day of the sql server recycled.
2010-03-09 (first published: 2010-02-18)
1,922 reads
Returns all properties from ServerProperty, also has a case function for EditionID and EngineEdition.
2010-03-08 (first published: 2010-02-18)
1,373 reads
This script will either reoprt or 'fix' lost or orphaned users after restore for all versions of SQL.
2010-02-24 (first published: 2010-02-04)
2,254 reads
Useful if you think a SQL statement, Function, or SPROC is taking too long to compile.
2010-02-23 (first published: 2010-02-04)
972 reads
By Steve Jones
“Don’t aim to have others like you; aim to have them respect you.” –...
Many years ago, before I joined Oracle, I was working on a major modernisation...
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
WhatsApp:0821-8154-398 Jl. KH. Wahid Hasyim No.20, Jombang, Kec. Jombang, Kabupaten Jombang, Jawa Timur 61415...
WhatsApp:0821-8154-398 9G9F+FFC, Jl. Jend. Sudirman No.79-81, Kejuron, Kec. Taman, Kota Madiun, Jawa Timur 63132...
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers