Find botched constraints, idxs, fks
Shows awesome view of columns with constraints and indexes and foreign keys to spot errors fast.
2010-08-04 (first published: 2009-12-03)
1,465 reads
Shows awesome view of columns with constraints and indexes and foreign keys to spot errors fast.
2010-08-04 (first published: 2009-12-03)
1,465 reads
2010-07-27 (first published: 2010-07-09)
2,168 reads
Ever happened that your custom log got rolled back and you were left with nothing but an error_message()?
Try to log into a table variable.
2010-07-22 (first published: 2010-06-30)
1,158 reads
2010-07-20 (first published: 2010-06-23)
2,586 reads
2010-07-19 (first published: 2009-11-16)
2,558 reads
2010-07-15 (first published: 2010-06-16)
1,916 reads
At times, we have situation to parse the character separated string in the table column.
2010-07-14 (first published: 2010-06-17)
2,214 reads
2010-07-08 (first published: 2010-06-17)
1,440 reads
This script provides comma separated values of one column for each value of another column. It provides it in SQL 2005 without using cursor.
2010-07-06 (first published: 2010-06-14)
2,311 reads
This is a quick way of outputting the location of your database files/dbsize/date created on your instance.
2010-07-02 (first published: 2010-06-06)
1,375 reads
By Steve Jones
I wrote about learning today for the editorial: I Can’t Make You Learn. I...
By ReviewMyDB
Fabric has CI/CD built in, but if you've tried to use it for database...
By Steve Jones
attriage – n. the state of having lost all control over how you feel...
Telp Cs: 08218200233 Jl. Merdeka No.39, Proklamasi, Kec. Siantar Bar., Kota Pematang Siantar, Sumatera...
Telp Cs: 08218200233 Jl. Asia, Simpang, Jl. Bakaran Batu No.1 C, Sei Rengas II,...
Telp Cs: 08218200233 Wisma Asia, Jl. Letjen S. Parman No.Kav. 79, RT.4/RW.9, Kota Bambu...
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers