2011-09-09 (first published: 2007-11-19)
8,948 reads
2011-09-09 (first published: 2007-11-19)
8,948 reads
Script one or all roles in a database. Includes users, obect permissions and column permissions.
2011-09-08 (first published: 2008-01-08)
5,290 reads
Generate the scripts that will allow you to compare tables pass/fail.
2011-09-07 (first published: 2007-12-28)
12,627 reads
2011-09-06 (first published: 2011-08-13)
1,992 reads
2011-09-05 (first published: 2007-01-25)
3,999 reads
This function returns the difference between the date in text format
2011-09-01 (first published: 2011-08-30)
1,064 reads
2011-08-31 (first published: 2011-08-24)
2,581 reads
Lists all the tables in a database that do not contain any LOB columns(text, ntext, image, varchar (max), nvarchar (max), varbinary (max) and xml).
Useful when rebuilding indexes online.
2011-08-30 (first published: 2011-08-25)
768 reads
Output table of gaps in a primary key across multiple databases on same, remote and/or linked servers.
2011-08-29 (first published: 2011-08-12)
970 reads
2011-08-24 (first published: 2011-08-12)
1,178 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
WhatsApp CS 628218520154 Jl. Suryopranoto No.40, RT.12/RW.7, Petojo Utara, Kecamatan Gambir, Kota Jakarta Pusat,...
WhatsApp CS 628218520154 Jl. Pegangsaan Timur No.1, Cikini, Kec. Menteng, Kota Jakarta Pusat, Daerah...
WhatsApp CS 628218520154 Jl. Pintu Air Raya No.36 Q, RT.6/RW.1, Ps. Baru, Kecamatan Sawah...
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers