Reverse-Engineer Database Permissions (2005 up)
This script reverse engineers SQL statements to recreate database permissions.
2011-10-24 (first published: 2011-10-07)
16,017 reads
This script reverse engineers SQL statements to recreate database permissions.
2011-10-24 (first published: 2011-10-07)
16,017 reads
Search for String Occurence with this script in your stored procedures.
2011-10-20 (first published: 2008-06-08)
5,370 reads
I have several problems with my corporate network and therefore need to do all my backups locally, and to make matters worse, still use SQL Server 2005.
2011-10-17 (first published: 2011-09-30)
430 reads
2011-10-14 (first published: 2011-08-24)
515 reads
Gets Detail table information such as partition information, compression, and partition range.
2011-10-13 (first published: 2011-09-30)
1,227 reads
2011-10-12 (first published: 2011-08-31)
940 reads
2011-10-10 (first published: 2011-08-24)
829 reads
This table Valued Function return the Modified Objects (SP /Views) For the Date specified.
2011-10-07 (first published: 2007-11-23)
1,381 reads
2011-10-06 (first published: 2007-11-14)
1,929 reads
The following script is used to check on the progress of a database restore, backup and other processes currently executing on SQL Server.
2011-10-05 (first published: 2011-09-09)
7,455 reads
By Steve Jones
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Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
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I've noticed several instances of what looks like a recursive insert with the format:...
Comments posted to this topic are about the item Cleaning Up the Cloud
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers