On Looking and Acting the Part
Phil Factor's offers tips for longevity in the world of IT consultancy: listen well, humiliate no-one and convince others that it was their expertise that solved the problem.
Phil Factor's offers tips for longevity in the world of IT consultancy: listen well, humiliate no-one and convince others that it was their expertise that solved the problem.
A 16-year old SQL Server bug that means 'forced plans' have the query plan hash in place of the expected query hash. Includes an explanation and discussion of the term 'morally equivalent plan'.
In this fifth level of the SSAS Tabular stairway, learn how to clean up dimensions.
For my new mission, I set out to convert a list of files from Excel to comma-separated values (CSV). We upload the original Excel files to a Data Lake in Fabric. We then need to convert a specific worksheet and move the CSV files to a different folder in Data Lake.
Over the past years, the tool dbt – short for data build tool – has become quite popular in the data engineering world for handling such an ELT process. dbt takes on the role of the “T”, meaning it’s responsible for transforming the data in a certain data store.
How to create a connection for StreamLit and Snowflake to upload data for visualization
How we handle data warehousing updates to dimension tables is crucial and this article covers Slowly Changing Dimensions versus overwriting tables.
By gbargsley
We’ve all been there. Someone walks up and asks, “Is SQL Server having issues?”...
By Chris Yates
In the beginning, there was OLTP – Online Transaction Processing. Fast, reliable, and ruthlessly...
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
Hello SQL Server 2022 16.0.4212.1 running on a Windows Server 2025 Std,V 24H2, SO...
i have subscription of github copilot which i can access in vs 2022 comunity...
Comments posted to this topic are about the item Password Guidance
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers