Trusting Source Control
One of the benefits of a version control system (VCS) is that you can look at the history of code changes. Ed Elliot shows us a situation where that helps a DBA track down a problem.
2015-06-30
5,145 reads
One of the benefits of a version control system (VCS) is that you can look at the history of code changes. Ed Elliot shows us a situation where that helps a DBA track down a problem.
2015-06-30
5,145 reads
Presents an open-source T-SQL based version tracking system for MSSQL
2015-01-22
8,063 reads
2014-09-12
1,730 reads
Thie article focuses on using SSIS to automatically check in the changes that the developers missed for the day into the version control system.
2012-12-18
856 reads
So, given the many good reasons for using Version Control systems for managing the changes in database applications, how does one go about the rather different routines of team development, such as testing, continuous integration, and managing data? What are the issues that you're likely to face?
2011-03-11
4,004 reads
This shows a method for generating scripts for SQL Server stored procedures and functions so they can be added to a version control management system (VCMS).
2010-05-06
20,859 reads
By Steve Jones
Here are the resources for my talk at Day of Data Boston. Slides –...
By Steve Jones
I’ve covered the values in a number of previous posts on the Book of...
By Arun Sirpal
When the evidence names the database, it says so. When it doesn’t, it stops....
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers