U-SQL

Stairway to U-SQL icon

Stairway to U-SQL Level 22: Creating a Custom Extractor

  • Stairway Step

Throughout this series, we’ve consistently dealt with delimited text files; comma and tab, for instance. We’ve used the U-SQL built-in extractors to process these files. But what if we need to deal with different types of file, like JSON, XML or fixed width? That’s where custom extractors come in. U-SQL provides us with the ability […]

★ ★ ★ ★ ★ ★ ★ ★ ★ ★

You rated this post out of 5. Change rating

2020-07-01

1,607 reads

Blogs

Goodbye, Microsoft

By

A few years ago I took a new job at Microsoft, working as a...

The SUM of Nothing: #SQLNewBlogger

By

I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...

How to Move the SSMS Status Bar to the Top and Color-Code SQL Server Connections

By

I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...

Read the latest Blogs

Forums

Today's AI

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Today's AI

Split Large Queries in Athena with a Simple Modulo Trick

By Rahul Gupta

Comments posted to this topic are about the item Split Large Queries in Athena...

Finding Trailing Spaces

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Finding Trailing Spaces

Visit the forum

Question of the Day

Finding Trailing Spaces

I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:

CustomerID CustomerName PreferredName
1          Steve        Steve               
2          Andy         Andy               
3          Brian        Brian               
4          Allan        Allan               
5          Devin        Devin               
6          Steve        Steve               
7          Sally        Sally
I want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT 
       CustomerID,
       CustomerName,
       PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName);

See possible answers