T-SQL

External Article

How to Avoid Conditional JOINs in T-SQL

  • Article

Relational databases go out of their way to execute SQL, however bad the crimes against Codd and relational theory within the query might be. The 'conditional join' can be executed, but at great cost. As always, it is much better to sit back and restate the problem in a set-based way - Dwain Camps explains.

2015-10-02

7,474 reads

External Article

T-SQL Window Functions Speed Phreakery

  • Article

Before SQL Server had SQL window functions, SQL Server developers had to use all manner of tricks and algorithms to come up with ways to rapidly process large amounts of data. Do we need these techniques now that we can express a SQL task in terms of window functions? Kathi revisits a famous SQL challenge to find out.

2015-09-18

4,213 reads

Blogs

Advice I Like: Respect

By

“Don’t aim to have others like you; aim to have them respect you.” –...

Blue Sky Programming – The Optimism Trap

By

Many years ago, before I joined Oracle, I was working on a major modernisation...

Setting Up a Mac for Data Engineering and AI Work

By

If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...

Read the latest Blogs

Forums

SQL Art, Part 4: Happy 4th of July — A British DBA's Guide to Celebrating a War We Don't Talk About

By Terry Jago

Comments posted to this topic are about the item SQL Art, Part 4: Happy...

Alamat kantor BCA KCP Galuh Mas Telp:0817866887

By Layanan_BCA_24jam

WhatsApp:0817-866-887 Area Street Festival, Ruko No 1 & 1A, CBD, Jl. Galuh Mas Raya,...

Is Fabric a Reliable Service or a Ripped Resource?

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Is Fabric a Reliable Service...

Visit the forum

Question of the Day

BIT_COUNT I

In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:

UserID  UserPermissions
15
23
37
What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount
from dbo.UserPermission
where UserID = 3;

See possible answers