Enterprise Architecture – Connect-the-Dots for Adults, Part 4
This article, part 4 in a series, discusses how to use, publish, maintain and govern the enterprise architecture.
2008-01-29
3,259 reads
Strategies
Application Locks (or Mutexes) in SQL Server 2005
Application locks aren't a well known area of locking in SQL Server, but they can be very useful for special scenarios. They work in an analogous way to the lock() construct in .Net and are basicaly user defined mutexes in SQL Server.
2008-01-15
4,038 reads
Are key performance indicators a true measure?
Some managers love to look solely at numbers when assessing performance, and key performance indicators (KPIs) are right up their street. But how useful are they in the context of software development
2007-10-12
3,591 reads
Are you innovating?
Andy has some examples of not very high tech solutions that involve some technology behind the scenes, but the binding factor was that someone had to see the problem first, and it wasn't one of those show stopper type problems. It's not about SQL, but we think it is on topic.
2004-09-30
5,302 reads
Blogs
Solving SQL Server Mysteries with a Whole Gang of Sleuths -Scooby Dooing Episode 4
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
SQL Server Availability Groups
By Kevin3NF
Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...
Modify Power BI page visibility and active status with Semantic Link Labs
Setting page visibility and the active page are often overlooked last steps when publishing...
Forums
Password Guidance
Comments posted to this topic are about the item Password Guidance
Using table variables in T-SQL
Comments posted to this topic are about the item Using table variables in T-SQL
Azure elastic query credential question
I am trying to check out elastic query between two test instances we have...
Question of the Day
Using table variables in T-SQL
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers