2020-08-12
261 reads
2020-08-12
261 reads
2020-07-25
378 reads
Intel is building hybrid processors, combining the power of the regular CPUs most of us use with Atom power saving technology.
2020-07-08
121 reads
A new security flaw in Intel SGX is found by researchers. This may or may not be a problem, but you should be aware.
2020-03-14
122 reads
Today Steve looks at a research project from Microsoft that provides some better protection from firmware security issues.
2019-12-17
159 reads
2019-10-18
390 reads
Some laptops are being banned from flights. This could be a hassle, but more, how can anyone tell if you have a banned one?
2019-08-29
405 reads
I remember buying my first computer after college. At the time I was working part time and in graduate studies part time. My aging high school era Apple II wasn't capable of handling the load, not to mention its 300baud modem wasn't a lot of fun. I could likely have gotten a faster modem with […]
2019-08-17
243 reads
AMD has new chips coming out and Glenn Berry changes his recommendation against using AMD in SQL Servers.
2019-07-20
191 reads
QNAP has introduced its USB 3.0 to 5 GbE network a...
2019-05-23
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
Comments posted to this topic are about the item The AI Bubble and the...
Hi, in a simple oledb source->derived column->oledb destination data flow, 2 of my...
hi, i noticed the sqlhealth extended event is on by default , and it...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers