2025-03-28
1,142 reads
2025-03-28
1,142 reads
The documentation cautions that cumulative updates (CU) could fail if a specific registry key isn’t updated after moving the master files, so I wanted to test this before I spent too much time configuring the server.
2025-03-12
Today Steve asks if you track the details of your table growth inside a database.
2025-03-07
178 reads
There may come a time when you want to or need to rename a database. In this tip we look at a couple different options.
2025-01-31
A 16-year old SQL Server bug that means 'forced plans' have the query plan hash in place of the expected query hash. Includes an explanation and discussion of the term 'morally equivalent plan'.
2024-12-27
2024-12-13
1,635 reads
2024-11-25
542 reads
The challenges of managing lots of system are significant and there aren't easy solutions, but Steve has a few thoughts on what you can do.
2024-11-18
252 reads
Let’s start with the Stack Overflow database (any size will work), drop all the indexes on the Users table, and run a delete:
2024-11-11
Learn about the ways in which you might better manage indexes for a better performing and efficient database.
2024-11-11
3,837 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
Comments posted to this topic are about the item The AI Bubble and the...
Hi, in a simple oledb source->derived column->oledb destination data flow, 2 of my...
hi, i noticed the sqlhealth extended event is on by default , and it...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers