Stairway to ScriptDOM Level 3 - Finding Patterns in the Abstract Syntax Tree
Learn how you can query for patterns in the Abstract Syntax Tree to analyze your code.
2023-02-22 (first published: 2022-06-08)
2,546 reads
Learn how you can query for patterns in the Abstract Syntax Tree to analyze your code.
2023-02-22 (first published: 2022-06-08)
2,546 reads
Should you always use EXISTS rather than COUNT when checking for the existence of any correlating rows that match your criteria? Does the former really offer "superior performance and readability". Louis Davidson investigates.
2019-11-28
Phil Factor demonstrates why SQL Prompt has a 'Best Practice' rule (BP010) that checks for use of the @@IDENTITY function, and suggests less error-prone ways to get the latest identity values used in a table.
2019-09-05
Database code analysis will reduce the number of 'code smells' that creep into your database builds. It will alert the team to mistakes or omissions, such as missing indexes, that are likely to cause performance problems in production. It will allow the Governance and Operations team visibility into production readiness of the code, warning them of security loopholes and vulnerabilities. William Brewer describes the two technical approaches to database code analysis, static and dynamic, and suggests some tools that can help you get started.
2017-08-18
3,546 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
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I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers