Architecture

External Article

Strengthening the Foundations of Software Architecture

  • Article

The term 'Architecture' seems to imply a plan that you can't easily subsequently deviate from. It's true that, if you abandon software architecture, you end up with a big ball of mud, but maybe the art of software is to make change much easier by planning how to implement each feature, tackling dependency issues, splitting functionality into small discrete components and considering how they should interact with each other.

2016-08-02

5,788 reads

External Article

Reporting@Home: Delivering Dynamic Graphical Feedback to Participants

  • Article

A new generation of computationally intensive scientific research projects relies on volunteers from around the world contributing idle computer time to calculate mathematical models. Many of these projects utilize a common architecture to manage the scheduling and distribution of calculations and collection of results from participants. User engagement is critical to the success of these projects, and feedback to participants illustrating their role in the project’s progress is known to increase interest and strengthen the community.

2007-08-07

2,040 reads

SQLServerCentral Article

New Features in Reporting Services 2005

  • Article

Reporting is one of the key parts of any data warehouse or business intelligence systems. Vincent Rainardi has brought us some great information on data warehousing and now turns his attention to some of the very useful new features in Reporting Services 2005.

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2008-05-26 (first published: )

10,635 reads

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Question of the Day

The Tightly Linked View

I try to run this code on SQL Server 2022. All the objects exist in the database.

CREATE OR ALTER VIEW OrderShipping
AS
SELECT cl.CityNameID,
       cl.CityName,
       o.OrderID,
       o.Customer,
       o.OrderDate,
       o.CustomerID,
       o.cityId
 FROM dbo.CityList AS cl
 INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID
GO
CREATE OR ALTER FUNCTION GetShipCityForOrder
(
    @OrderID INT
)
RETURNS VARCHAR(50)
WITH SCHEMABINDING
AS
BEGIN
    DECLARE @city VARCHAR(50);
    SELECT @city = os.CityName
    FROM dbo.OrderShipping AS os
    WHERE os.OrderID = @OrderID;
    RETURN @city;
END;
go
What is the result?

See possible answers