Happy Anniversary!
Today, http://mssqlfun.com/ completed 2 precious years with your support & acknowledgment. It’s wonderful time enriched with fun & learning.
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2014-06-12
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Today, http://mssqlfun.com/ completed 2 precious years with your support & acknowledgment. It’s wonderful time enriched with fun & learning.
Please keep liking us...
2014-06-12
774 reads
SQL Server 2012 Service Pack 2 (SP2) RTM is now available for download at the Microsoft Support site. Service Pack...
2014-06-12
1,506 reads
Microsoft declares to release last & final service packs for SQL Server 2008 and SQL Server 2008 R2 very soon.
Mainstream Support...
2014-06-12
937 reads
I frequently see the default trace mentioned in answers to forum questions, blog posts, articles, even training sessions. My knowledge...
2014-06-12
859 reads
Readers of my blog would be pleased to know that I have teamed up with Packt Publishing and we are...
2014-06-12
726 reads
This post follows on from the previous post Partitioning Basics – Part 1
Let’s have a look at the partitions setup in...
2014-06-12
1,065 reads
If you are running VMware vSphere 5.5 Update 1 and are using NFS-connected storage, update your hosts ASAP (test first,...
2014-06-12
645 reads
2014-06-12
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2014-06-12
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2014-06-12
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By SQLPals
How to Clear the SSMS Cache (SSMS 21 and Later) Updated...
By Arun Sirpal
“What exactly did it do on my server?” is the first question a DBA...
By James Serra
Microsoft shared a broad set of Fabric, Power BI, and SQL updates at FabCon...
Comments posted to this topic are about the item Let's Talk Certifications
Comments posted to this topic are about the item The Hidden Security Risks of...
Comments posted to this topic are about the item The Empty Aggregate
I have this table in a SQL Server 2025 database:
CREATE TABLE [dbo].[CustomerOrder] ( [OrderID] [int] NULL, [CustomerID] [int] NULL, [total] [money] NULL ) ON [PRIMARY] GOWhat is returned from this code? (answers are for the sum and then the count)
SELECT SUM(total) AS sum,
COUNT(total) AS count
FROM dbo.CustomerOrder;
See possible answers