Blog Posts

Blog Post

AWS RDS SQL Server Announcements - 2019

1.    Amazon RDS SQL Server Supports differential and log and restores: https://aws.amazon.com/about-aws/whats-new/2019/11/amazon-rds-for-sql-server-now-supports-differential-restores-and-log-restores/ 

2.    Amazon RDS SQL Server now supports logs to cloudwatch: https://aws.amazon.com/about-aws/whats-new/2019/11/now-publish-log-files-amazon-rds-sql-server-amazon-cloudwatch/ 

3.    Amazon RDS SQL Server now supports high availability in...

2020-01-29

421 reads

Blog Post

Insperation

Inspiration: The process of being mentally stimulated to do or feel something, especially to do something creative. a person or ... Continue reading

2020-01-29

13 reads

Blog Post

Coping with Self Doubt

One of the best coping mechanisms for Impostor Syndrome is the use of learned behaviors. This article shares some of these coping mechanisms and learned behaviors.
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Passion, Challenges, and...

2020-01-28 (first published: )

637 reads

Blogs

Solving SQL Server Mysteries with a Whole Gang of Sleuths -Scooby Dooing Episode 4

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One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...

SQL Server Availability Groups

By

Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...

Modify Power BI page visibility and active status with Semantic Link Labs

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Setting page visibility and the active page are often overlooked last steps when publishing...

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Forums

Password Guidance

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Password Guidance

Using table variables in T-SQL

By Alessandro Mortola

Comments posted to this topic are about the item Using table variables in T-SQL

Azure elastic query credential question

By cphite

I am trying to check out elastic query between two test instances we have...

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Question of the Day

Using table variables in T-SQL

What happens if you run the following code in SQL Server 2022+?

declare @t1 table (id int);

insert into @t1 (id) values (NULL), (1), (2), (3);

select count(*)
from @t1
where @t1.id is distinct from NULL;
 

See possible answers