Phil Factor Speed Phreak SQL Challenge Number 3
The latest Phil Factor challenge is now active here . The prize has now been increased to $100...(read more)
2009-12-04
428 reads
The latest Phil Factor challenge is now active here . The prize has now been increased to $100...(read more)
2009-12-04
428 reads
I traveled quite a bit in 2009, hitting 3 SQL Saturdays, 5 user groups and a few other events during...
2009-12-03
423 reads
In the previous post in this series, I discussed the obstacles to implementing electronic health data systems. Because of these...
2009-12-03
1,393 reads
From a Forrester blog: Ten eReader and eBook predictions for 2010.
It’s an interesting read, and I tend to agree with...
2009-12-03
2,235 reads
Let's face it, when it comes to computers there's a 100% certainty that something is going to break eventually. Maybe...
2009-12-03
589 reads
Pinal Dave had a helpful post a few days ago about how to setup and configure SQL Azure. You will...
2009-12-03
1,377 reads
We have covered the Hard Disk and the System Bus. This time around we will cover disk controllers and host...
2009-12-03
6,472 reads
This is part three in a series of blog posts that will help you build an arsenal of MDX calculations...
2009-12-03
1,771 reads
Last week I posted about planning to cook some for Thanksgiving, thought this week I’d share some of how it...
2009-12-03
474 reads
Everyone who wants to know about how transaction replication works and how to improve the performance of transaction replication must...
2009-12-03
2,148 reads
By Steve Jones
It’s Prime Day. A few of my recommendations, since I want to do some...
With Fabric Mirroring, Microsoft is promoting a nice and appealing story for operational reporting...
If you’ve been watching AI roll through the data community and thinking, “this seems...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
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I set up a few users on my SQL Server 2022 instance.
CREATE LOGIN User1 WITH PASSWORD = 'Demo12#1' CREATE USER User1 FOR LOGIN User1 GO CREATE LOGIN User2 WITH PASSWORD = 'Demo12#2' CREATE USER User2 FOR LOGIN User2 GO CREATE LOGIN User3 WITH PASSWORD = 'Demo12#3' CREATE USER User3 FOR LOGIN User3 GOI then created a schema that one of them owned. Under this schema, I added a table with some data.
CREATE SCHEMA MySchema AUTHORIZATION User1
GO
CREATE TABLE Myschema.MyTable(myid INT)
GO
INSERT MySchema.MyTable
(
myid
)
VALUES
(1), (2), (3)
GO
SELECT * FROM MySchema.MyTable
GO
I granted rights and verified that User2 could access this table.
GRANT SELECT ON Myschema.MyTable TO User2 GO SETUSER 'USER2' GO SELECT * FROM MySchema.MyTable GOThis worked. Now, I move this schema to a new user.
ALTER AUTHORIZATION ON SCHEMA::Myschema TO User3; GOWhat happens with this code?
SETUSER 'USER2' GO SELECT * FROM MySchema.MyTable GOSee possible answers