Next Step for the One Laptop Per Child Project
I’ve been a fan of the OLPC project, even buying to raffle off at an event just so I could...
2010-02-08
352 reads
I’ve been a fan of the OLPC project, even buying to raffle off at an event just so I could...
2010-02-08
352 reads
Ok Guys and Gals. I know I have been a slow blogger thus far in 2010. To try and make...
2010-02-08
348 reads
Scott Klein has put together the first annual Geek Golf event. Scheduled for May 8th, 2010, it’s being held at...
2010-02-08
524 reads
I'll be presenting two sessions this week (February 9 and 11, 2010), both on SQL Server Indexing. The first is...
2010-02-08
351 reads
If you haven't seen the Simple-Talk newsletter (it's free, so sign up!) you may not have seen my article on...
2010-02-08
1,270 reads
I saw a post recently from my fellow Red Gate-er, Brad McGeHee, on backups. Brad’s got a ton of experience...
2010-02-07
427 reads
I have been trying for a few days to implement a Service Broker implementation to, service the threading framework I...
2010-02-07
547 reads
I have been trying for a few days to implement a Service Broker implementation to, service the threading framework I...
2010-02-07
1,789 reads
They say that imitation is the sincerest form of flattery. I have been following along as Paul Randal has been...
2010-02-07
4,338 reads
This is a short post on SQL Server storage best practice and what i have learned over the years… Much...
2010-02-07
1,345 reads
By Steve Jones
I wrote about learning today for the editorial: I Can’t Make You Learn. I...
By ReviewMyDB
Fabric has CI/CD built in, but if you've tried to use it for database...
By Steve Jones
attriage – n. the state of having lost all control over how you feel...
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Comments posted to this topic are about the item SSRS Reminded Me of the...
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers