Upcoming Free Webinars on Database Development and Operations
Fall is in swing, and it’s officially webinar season! Here’s a bunch of free events I’ve got on my calendar. Weekly Database DevOps Live Chats – a new experiment...
2019-11-19
3 reads
Fall is in swing, and it’s officially webinar season! Here’s a bunch of free events I’ve got on my calendar. Weekly Database DevOps Live Chats – a new experiment...
2019-11-19
3 reads
2019-11-16
5 reads
2019-11-16
8 reads
Steve Jones and I had a great time today talking about source control for databases and release patterns for performance and availability in Seattle. We had a great group...
2019-11-06
22 reads
2019-11-06
3 reads
2019-11-06
5 reads
I’ve observed few similarities between the Project Managers and Advocates. Being Project Manager, law bachelor and little practical experienced as an Advocate, I noticed few similarities. I think it’s...
2019-11-04
8 reads
I’ve observed few similarities between the Project Managers and Advocates. Being Project Manager, law bachelor and little practical experienced as an Advocate, I noticed few similarities. I think it’s...
2019-11-04
17 reads
A series of articles that will talk about most important but least focused areas in Database Design and Development.
2019-10-31
5 reads
A series of articles that will talk about most important but least focused areas in Database Design and Development.
2019-10-31
4 reads
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
By Kevin3NF
Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...
Setting page visibility and the active page are often overlooked last steps when publishing...
Comments posted to this topic are about the item Password Guidance
Comments posted to this topic are about the item Using table variables in T-SQL
I am trying to check out elastic query between two test instances we have...
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers