The Impact of Outages
Steve Jones talks about the problems of outages, and why we ought to perhaps introduce failure into our systems to help us learn to cope with them.
2011-08-01
75 reads
Steve Jones talks about the problems of outages, and why we ought to perhaps introduce failure into our systems to help us learn to cope with them.
2011-08-01
75 reads
This Friday Steve Jones has a non-work related, but fun poll. Let us know what your geeky media recommendations are this year.
2011-07-29
137 reads
I saw this question come across Twitter under the #sqlhelp tag one day and was wondering myself. Someone suggested the...
2011-07-28
7,595 reads
Today Steve Jones tells you can implement telecommuting at your job and gives you a few ideas how to get it approved.
2011-07-28
229 reads
Steve Jones looks to the future of SQL Server and wonders if we ought to add a rowid to the internal structures.
2011-07-27
224 reads
A new breed of products use the relational model and address the scalability concerns of many RDBMSes. Today Steve Jones talks about NewSQL databases.
2011-07-26
219 reads
2011-07-26
2,209 reads
Steve rounds up the patch news for SQL Server this week along with a look forward to the next version of the platform.
2011-07-25
117 reads
Be reasonable. That's how Steve Jones thinks managers ought to behave towards their employees.
2011-07-21
153 reads
2011-07-21
2,456 reads
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
By Kevin3NF
Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...
Setting page visibility and the active page are often overlooked last steps when publishing...
Comments posted to this topic are about the item Password Guidance
Comments posted to this topic are about the item Using table variables in T-SQL
I am trying to check out elastic query between two test instances we have...
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers