Security is Getting Serious
Today Steve Jones notes that back doors could be inserted into chips, which would be a huge problem.
2016-07-18
95 reads
Today Steve Jones notes that back doors could be inserted into chips, which would be a huge problem.
2016-07-18
95 reads
2016-07-18
1,072 reads
I’m heading down to Austin next weekend for MeasureUp 2016. This is a Microsoft stack conference that looks to help...
2016-07-16
557 reads
This is a series of posts on the PASS Summit and SQL Saturdays. I’m outlining some thoughts here, sometimes for...
2016-07-15 (first published: 2016-07-05)
1,088 reads
This Friday, Steve Jones asks if you're like to work remotely. With the trend moving this way, mostly for extra hours, maybe you'd like to move that way for most of your work time.
2016-07-15
211 reads
2016-07-15
1,387 reads
Another post for me that is simple and hopefully serves as an example for people trying to get blogging as...
2016-07-14
872 reads
2016-07-14
1,445 reads
Next Tuesday is the next installment of our DLM series from Redgate. I’m off the hook, with Grant and Arneh...
2016-07-13
575 reads
MongoDB can lose some rows in queries run very close together. Is that bad? Steve Jones thinks so, though this doesn't mean you shouldn't use MongoDB or any other NoSQL database.
2016-07-13
127 reads
A RAG pipeline that answers questions in the demo is not the same thing...
By Steve Jones
“A multitude of bad ideas is necessary for one good idea” – from Excellent...
Yesterday I gave a talk for MSSQLTips called “Building a DBA Agent for Your...
Comments posted to this topic are about the item Adding new column with DEFAULT
I've got a web application for my side business. I've added a SQL Server...
Comments posted to this topic are about the item Looking for New Blood
Which number will the COUNT() return after executing the following statements:
DROP TABLE IF EXISTS #test; CREATE TABLE #test (id INT) INSERT INTO #test (id) SELECT * FROM GENERATE_SERIES(1, 3) AS gs ; ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0; go UPDATE #test SET flag = 0 WHERE id = 1 UPDATE #test SET flag = 1 WHERE id = 2 INSERT INTO #test (id) VALUES (4) SELECT COUNT(*) FROM #test AS t WHERE flag = 0See possible answers