The Snippet Manager in SQL Prompt
I love SQL Prompt, since it makes T-SQL coding quicker and easier. One of the handiest things is the Snippet...
2016-10-12
723 reads
I love SQL Prompt, since it makes T-SQL coding quicker and easier. One of the handiest things is the Snippet...
2016-10-12
723 reads
2016-10-12
1,212 reads
SQL Server should work to make it easy for developers to work with it, and include versions like Express in their applications.
2016-10-11 (first published: 2010-09-08)
374 reads
On Monday, October 24, 2016, there will be a Free-Con in Seattle for those that might not be attending a...
2016-10-11
440 reads
This month is an interesting T-SQL Tuesday topic, and it’s brought to us by Andy Mallon, with the topic of...
2016-10-11
613 reads
2016-10-11
1,386 reads
It’s PASS Summit time and that means Andy Warren and I are doing another Monday Night Networking Dinner.
For those of...
2016-10-10
548 reads
I hope everyone is well in Florida, but the hurricane caused a postponement of SQL Saturday Orlando. Fortunately I caught...
2016-10-07
427 reads
This Friday Steve Jones talks about your support load. Let us know how many databases you support and what the load is like.
2016-10-07 (first published: 2012-10-26)
252 reads
2016-10-07
1,052 reads
A RAG pipeline that answers questions in the demo is not the same thing...
By Steve Jones
“A multitude of bad ideas is necessary for one good idea” – from Excellent...
Yesterday I gave a talk for MSSQLTips called “Building a DBA Agent for Your...
Comments posted to this topic are about the item Adding new column with DEFAULT
I've got a web application for my side business. I've added a SQL Server...
Comments posted to this topic are about the item Looking for New Blood
Which number will the COUNT() return after executing the following statements:
DROP TABLE IF EXISTS #test; CREATE TABLE #test (id INT) INSERT INTO #test (id) SELECT * FROM GENERATE_SERIES(1, 3) AS gs ; ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0; go UPDATE #test SET flag = 0 WHERE id = 1 UPDATE #test SET flag = 1 WHERE id = 2 INSERT INTO #test (id) VALUES (4) SELECT COUNT(*) FROM #test AS t WHERE flag = 0See possible answers