2020-08-13 (first published: 2016-04-18)
517 reads
2020-08-13 (first published: 2016-04-18)
517 reads
When I got a new machine, I had SQL Clone on my old machine, in a few VMWare VMs. I decided to move this to my new machine, so...
2020-08-13 (first published: 2020-08-04)
349 reads
I started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2020-08-12
34 reads
2020-08-12
261 reads
2020-08-12
385 reads
One of the things I’ve tried to do when SQL Saturdays is ensure there are lots of local speakers, and new speakers. I’ve argued for more new speakers at...
2020-08-12
4 reads
Unsecured databases are a problem, but someone is fighting this issue by wiping them out.
2020-08-11
193 reads
I started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2020-08-11
10 reads
This month the T-SQL Tuesday invitation comes from Tamara Clark. I strong-armed Tamara last fall, along with her husband, into hosting this year. She came through, with a great...
2020-08-11
16 reads
2020-08-11
801 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
Comments posted to this topic are about the item The AI Bubble and the...
Hi, in a simple oledb source->derived column->oledb destination data flow, 2 of my...
hi, i noticed the sqlhealth extended event is on by default , and it...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers