Jumping the Gun
How quickly should security issues be reported? Steve Jones isn't sure, but he talks a bit about what we might want to do.
2008-10-01
254 reads
How quickly should security issues be reported? Steve Jones isn't sure, but he talks a bit about what we might want to do.
2008-10-01
254 reads
2008-10-01
2,128 reads
Managing DBAs can be a challenge for both sides. Steve Jones talks a bit about some of his relationships with managers and the trouble that sometimes occurs.
2008-09-30
247 reads
Steve Jones talks a bit more about the employee manager relationship in this turbulent times.
2008-09-30
70 reads
Steve Jones talks a bit more about the employee manager relationship in this turbulent times.
2008-09-30
63 reads
Steve Jones talks a bit more about the employee manager relationship in this turbulent times.
2008-09-30
65 reads
Always something going wrong around here with the podcasts. Today I was editing a couple, or attempting to, and couldn't...
2008-09-29
1,440 reads
A new SQL Server system has claimed the top spots in the TPC-E benchmark, but Steve Jones doesn't think it's that impressive.
2008-09-29
48 reads
Why did I write this? I got challenged by Andy Warren
to write a bit about why I wrote something. I...
2008-09-29
1,354 reads
This month's car update focuses mainly on the Prius and changes that might coming in the car industry.
2008-09-29
171 reads
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
By Kevin3NF
Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...
Setting page visibility and the active page are often overlooked last steps when publishing...
Comments posted to this topic are about the item Password Guidance
Comments posted to this topic are about the item Using table variables in T-SQL
I am trying to check out elastic query between two test instances we have...
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers