2018-09-21 (first published: 2016-01-04)
6,352 reads
2018-09-21 (first published: 2016-01-04)
6,352 reads
2018-08-10 (first published: 2015-10-05)
4,915 reads
Have experience editing and writing technical content? Redgate is currently hiring for their educational publishing site, Simple Talk. They're open to accepting remote workers, so if you're interested, there's no excuse not to go ahead and apply!
2017-08-01 (first published: 2017-07-28)
4,722 reads
A look at the positive and negative aspects of IoT in this infographic.
2017-02-01
248 reads
2017-01-03
2,386 reads
Here is a reference that lets you take a quick look at the new features in SQL Server 2016 and dig into the various items with a collection of links we'll maintain.
2016-10-28 (first published: 2015-06-22)
14,421 reads
We're always looking for articles, but here are a few ones that I'd like to see written up.
2016-04-29 (first published: 2014-09-04)
1,987 reads
2015-11-09
114 reads
Links and references to understand what the Query Store is in SQL Server 2016.
2015-09-28
2,823 reads
References and links about the Stretch to Azure feature in SQL Server 2016.
2015-09-21
1,379 reads
By HeyMo0sh
One of the biggest challenges I’ve faced in cloud operations is maintaining clear visibility...
By Steve Jones
I come to Heathrow often. Today is likely somewhere close to 60 trips to...
By Brian Kelley
If your organization is spending money, then meaningful results are a must. Pen testing...
Comments posted to this topic are about the item Fun with JSON II
Comments posted to this topic are about the item Changing Data Types
Comments posted to this topic are about the item Answering Questions On Dropped Columns
I have some data in a table:
CREATE TABLE #test_data
(
id INT PRIMARY KEY,
name VARCHAR(100),
birth_date DATE
);
-- Step 2: Insert rows
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT t1.[key] AS row,
t2.*
FROM OPENJSON(
(
SELECT t.* FROM #test_data AS t FOR JSON PATH
)
) t1
CROSS APPLY OPENJSON(t1.value) t2; See possible answers