SQL Server Rounding Tips and Tricks
This article shows different options to use the rounding functions in SQL Server.
2020-04-17 (first published: 2016-09-20)
24,755 reads
This article shows different options to use the rounding functions in SQL Server.
2020-04-17 (first published: 2016-09-20)
24,755 reads
Snippets will allow you to code faster by inserting chunks of code with few key strokes.
2018-08-17 (first published: 2016-04-07)
11,497 reads
Using wildcard to find patterns in strings going from the basics to some more complicated conditions.
2017-02-10 (first published: 2015-09-29)
19,412 reads
Set-based programming doesn’t mean “no loops” or a single statement. Finding out the best ways to traverse a full hierarchy.
2016-10-07 (first published: 2015-07-27)
24,968 reads
2015-11-18 (first published: 2015-10-29)
1,073 reads
Calculating working hours can be painful due to all the variances that they imply. This function will calculate working hours between 2 dates which might include time. There's an option to use a holidays table that will vary in each environment.
2015-10-22 (first published: 2014-05-22)
3,761 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers