In most tables it is enough to have a stored procedure that performs Update Else Insert logic for data managment. However, in some cases we do not want to destroy the old data with an update statement. Instead we want to maintain history up to a certain number of versions. This article presents a method for doing so.
2001-08-27
3,337 reads
A great deal of data in any RDBMS is hierarchial. This article presents a technique for aggregating this data.
2001-08-22
3,088 reads
Sometimes it is necessary to save binary data such as zip files, pictures or office documents into the database. This article looks at a way of using Java to perform this task.
2001-08-07
8,838 reads
The following stored procedure will demonstrate the use of cursor metadata. Using cursor metadata we can get information about an SQL statement and use that information to dynamically generate other code such as HTML or other stored procedures.
2001-07-27
5,368 reads
This article presents a method of outputting the results of a query as a tab delimited text file using COM.
2001-07-20
6,608 reads
Lots of applications store user names and passwords in the database. This article presents a method for encypting this information using Java.
2001-07-19
15,014 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
WhatsApp CS 628218520154 Jl. Pintu Air Raya No.36 Q, RT.6/RW.1, Ps. Baru, Kecamatan Sawah...
Comments posted to this topic are about the item Split Large Queries in Athena...
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers