2011-08-31 (first published: 2011-08-24)
2,500 reads
2011-08-31 (first published: 2011-08-24)
2,500 reads
2011-06-07
3,461 reads
2011-05-17
3,174 reads
This script is used for drop and create a new or existing user. IF User is already exists in database then first it will dropped and then recreate.
2011-05-11 (first published: 2011-04-28)
1,783 reads
2011-04-26 (first published: 2011-04-20)
2,657 reads
This script show a demonstration of how to interst tore Procedure Output in a Table.
2010-01-08 (first published: 2009-12-18)
2,484 reads
2009-05-11
4,535 reads
2009-02-26
3,586 reads
2009-02-19
3,242 reads
2009-02-16 (first published: 2009-02-03)
2,623 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers