Upcoming Free Webinars on Database Development and Operations
Fall is in swing, and it’s officially webinar season! Here’s a bunch of free events I’ve got on my calendar. Weekly Database DevOps Live Chats – a new experiment...
2019-11-19
3 reads
Fall is in swing, and it’s officially webinar season! Here’s a bunch of free events I’ve got on my calendar. Weekly Database DevOps Live Chats – a new experiment...
2019-11-19
3 reads
2019-11-16
5 reads
2019-11-16
8 reads
Steve Jones and I had a great time today talking about source control for databases and release patterns for performance and availability in Seattle. We had a great group...
2019-11-06
22 reads
2019-11-06
3 reads
2019-11-06
5 reads
I’ve observed few similarities between the Project Managers and Advocates. Being Project Manager, law bachelor and little practical experienced as an Advocate, I noticed few similarities. I think it’s...
2019-11-04
8 reads
I’ve observed few similarities between the Project Managers and Advocates. Being Project Manager, law bachelor and little practical experienced as an Advocate, I noticed few similarities. I think it’s...
2019-11-04
17 reads
A series of articles that will talk about most important but least focused areas in Database Design and Development.
2019-10-31
5 reads
A series of articles that will talk about most important but least focused areas in Database Design and Development.
2019-10-31
4 reads
Setting page visibility and the active page are often overlooked last steps when publishing...
By Steve Jones
It’s time for T-SQL Tuesday again and this time Todd Kleinhans has a great...
By Steve Jones
Recently I was working in VS Code and I saw a walkthrough for the...
Comments posted to this topic are about the item Password Guidance
Comments posted to this topic are about the item Using table variables in T-SQL
I am trying to check out elastic query between two test instances we have...
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers