Arun Sirpal

I am a Senior DBA with interest in MS technology especially SQL Server and Azure. During 2015 I was mentored by Paul Randal – Data Platform (SQL Server) MVP and during 2016 I completed my SQLskills Immersion training on Internals and Performance Tuning. When I am not working I am in the gym burning calories.

All authors

Blog Post

Interviews and Oranges

What a great topic for this month’s T-SQL Tuesday hosted by Kendra Little https://littlekendra.com/2017/08/01/tsql-tuesday-93-interviewing-patterns-anti-patterns/

The topic being: Interviewing Patterns and Anti-Patterns....

2017-08-08

312 reads

All authors

Blogs

Advice I Like: Art

By

Superheroes and saints never make art. Only imperfect beings can make art because art...

Why Optimize CPU for RDS SQL Server is a game changer

By

One feature that I have been waiting for years! The new announcement around optimize...

Performance tuning KubeVirt for SQL Server

By

Following on from my last post about Getting Started With KubeVirt & SQL Server,...

Read the latest Blogs

Forums

data type gets lost in data flow

By stan

Hi, in a simple oledb source->derived column->oledb destination    data flow, 2 of my...

i noticed the sqlhealth extende event is on by default , so can i reduce

By rajemessage 14195

hi, i noticed the sqlhealth extended event is on by default , and it...

New-AzSqlInstanceServerTrustCertificate - Failed and no clues

By BrainDonor

Using New-AzSqlInstanceServerTrustCertificate to import a certificate and get the message New-AzSqlInstanceServerTrustCertificate: Long running operation...

Visit the forum

Question of the Day

The Read Committed Snapshot Isolation behaviour

I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON: 

use master;
go

alter database AdventureWorks set read_committed_snapshot on with no_wait;
go
Then, from Session 1, I execute the following code: 
--Session 1
use AdventureWorks;
go

create table ##t1 (id int, f1 varchar(10));
go

insert into ##t1 values (1, 'A');
From another session, called Session 2, I open a transaction and execute the following update: 
--Session 2
use AdventureWorks;
go

begin tran;
update ##t1 
set f1 = 'B'
where id = 1;
Now, going back to Session 1, what happens if I execute this statement? 
--Session 1
select f1
from ##t1
where id = 1;
 

See possible answers